You flip three coins (a nickel, a dime, and a quarter), assigning the values of +1 for heads (H) and –1 for tails (T). Each outcome after flipping the three coins constitutes a microstate. How many microstates are possible by flipping these three coins?

8 possible microstates.

Explanation:

Supposed we tossed three (3) coins (a nickel, a dime, and a quarter).

The possible outcomes can be seen as follows.

Coin

1st. +1 +1 +1 -1 +1 -1 -1 -1

2nd +1 +1 -1 +1 -1 +1 -1 -1

3rd +1 -1 +1 +1 -1 -1 +1 -1

There 8 (eight) microstates are possible.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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