At a certain concentration of H2 and I2, the initial rate of reaction is 4.0 x 104 M / s. What would the initial rate of the reaction be if the concentration of H2 were halved? Round your answer to

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

At a certain concentration of and , the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of

Answer : The initial rate of the reaction will be,  

Explanation :

Rate law expression for the reaction:

As we are given that:

Initial rate = 4.0 × 10⁴ M/s

Expression for rate law for first observation:

....(1)

Expression for rate law for second observation:

....(2)

Dividing 2 by 1, we get:

Therefore, the initial rate of the reaction will be,

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answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).