A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressure of the gas from 43 atm to 17 atm. Assume that the volume of the tank and the temperature of the oxygen are constant during this operation. Answer in units of g.

12.8 g of must be withdrawn from tank

Explanation:

Let's assume gas inside tank behaves ideally.

According to ideal gas equation-

where P is pressure of , V is volume of , n is number of moles of , R is gas constant and T is temperature in kelvin scale.

We can also write,

Here V, T and R are constants.

So, ratio will also be constant before and after removal of from tank

Hence,

Here, and

So,

So, moles of must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of = 32 g/mol

So, mass of must be withdrawn =

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.