When 2.50g of hydrochloric acid reacts with 1.50g of potassium hydroxide to yiel
potassium chloride and water, how many grams of potassium chloride are
produced? What is the limiting reactant between hydrochloric acid and potassium
hydroxide ?

1.50  grams of potassium chloride are produced

Potassium hydroxide is the limiting reactant

Explanation:

HCl + KOH→KCl + H₂O

HCl and KOH react on a 1 : 1 mole ratio. They also produce products on a 1 : 1 ratio.

The limiting reagent, in this case, is KOH because it will be fully exhausted in the reaction while the excess HCl will be left remaining.

The remaining HCL will be 2.50 g – 1.50 g

= 1g

Remember because both reactants react at a 1: 1 ratio

In addition, 1.50 g on KCl will be formed in the products

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.