HELP PLZ, GIVING BRAINLIEST!!
Calculate the volume required to dissolve 11.2 g of CuS04 to prepare a 0.140M solution. Show work, please.

The answer to your question is 500 ml

Explanation:

Data

Volume = ?

mass of CuSO₄ = 11-2 g

concentration = 0.14 M

Process

1.- Calculate the molar mass of CuSO₄

CuSO₄ = 64 +32 + (16 x 4)

           = 64 + 32 + 64

           = 160 g

2.- Calculate the number of moles

              160 g of CuSO₄ 1 mol

                 11.2 g of CuSO₄ x

               x = (11.2 x 1)/160

               x = 0.07 moles

3.- Calculate the volume

Molarity = moles/ volume

Solve for volume

Volume = moles/Molarity

Substitution

Volume = 0.07/0.140

Simplification

Volume = 0.5 L

Result = 500 ml

We need 501 mL to dissolve 11.2 grams of CuSO4

Explanation:

Step 1: Data given

Mass of CuSO4 = 11.2 grams

Molarity CuSO4 = 0.140 M

Molar mass = 159.61 g/mol

Step 2: Calculate moles CuSO4

Moles CuSO4 = mass CuSO4 / molar mass

Moles CuSO4 = 11.2 grams / 159.61 grams

Moles CuSO4 = 0.0702 moles

Step 3: Calculate volume

Volume = moles /molarity

Volume = 0.0702 moles / 0.140 M

Volume = 0.501 L

We need 501 mL to dissolve 11.2 grams of CuSO4

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.