For the reaction 3 C 2H 2( g) → C 6H 6( l) at 25°C, the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K. Calculate the standard free energy change at 25°C

The standard free energy change is -502.86 KJ

Explanation:

ΔG° = H° -TΔS°

where;

ΔG° is the standard free energy

H° is the standard enthalpy change = -631 kJ

ΔS° is the standard change in entropy = -430 J/K

T is the temperature of the system = 25⁰C = 298 K

Applying the formula above;

ΔG° = -631 kJ - ( -0.43J/K × 298K)

      = -631 kJ + 128.14 KJ

      = -502.86 KJ

Therefore, the standard free energy change is -502.86 KJ

law of conservation of matter

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!