Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH-] is
1x10 ^-12 mol/L

1x10^-2mol/L

Explanation:

[OH-] = 1x10 ^-12 mol/L

Recall:

[H+] x [OH-] = 1x10^-14

[H+] x 1x10 ^-12 = 1x10^-14

Divide both side by 1x10 ^-12

[H+] = 1x10^-14/ 1x10 ^-12

[H+] = 0.01 = 1x10^-2mol/L

im not exactly sure but i think its b!

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