Using the Brønsted-Lowry concept of acids and bases, identify the Brønsted-Lowry acid and base in each of the following reactions: HS−(aq)+H2O(l)→H2S(aq)+OH−(aq) (CH3)3N(g)+BCl3(g)→(CH3)3NBCl3(s)

Explanation:

A Brønsted-Lowry acid is any species capable of donating a proton (H +).

A Brönsted-Lowry base is a substance capable of winning or accepting a proton (H +).

Then there is a transfer of protons that requires the presence of a proton donor, that is, an acid and a base that accepts them. Thus, the acid-base reaction is one in which the acid transfers a proton to a base.

In the first case you have:

HS⁻ + H₂O → H₂S + OH⁻

You can see that the HS⁻ has become H₂S. This indicates that it has accepted a proton (H⁺), so, according to the definitions seen, it is a Brønsted-Lowry base.  

H₂O has become OH⁻. As it has an H + less proton, it is possible to say that it has donated said proton, so it is a Brønsted-Lowry acid.

When an acid donates a proton, this acid is called a conjugate base. On the contrary, when a base receives a proton it is known as conjugate acid. This is called conjugate acid-base pairs. And this is what occurs in this case.

In the other case you have:

(CH₃)₃N(g)+BCl₃(g)→(CH₃)₃NBCl₃(s)

In this case there is no transfer of a proton from an acid to a base. So this reaction cannot be explained by the Brønsted-Lowry theory.

anaphase.

hope this !

it's c (engineer's do their work with mechanical stuff not on any living being)