A solution with a total volume of 1000.0 mL contains 37.1 g Mg(NO3)2. If you remove 20.0 mL of this solution and then dilute this 20.0 mL sample with water until the new volume equals 500.0 mL, what is the concentration of Mg 2 ion in the 500.0 mL of solution?

0.01023 M  is the concentration of Mg 2 ion in the 500.0 mL of solution.

Explanation:

Mass of magnesium nitrate = 37.1 g

Moles of magnesium nitrate =

Volume of the solution = 1000.0 mL = 1.0 L ( 1000 mL = 1 L)

Molarity of the solution =

Molarity of the magnesium nitrate solution before dilution =

Volume of the magnesium nitrate solution before dilution =

Molarity of the magnesium nitrate solution after dilution =

Volume of the magnesium nitrate solution after dilution =

(dilution )

Molarity of the magnesium nitrate solution after dilution is 0.01023 M.

1 mole of magnesium nitrate gives 1 mole of magnesium ions.Then in 0.01023 M solution of magnesium nitrate;

0.01023 M  is the concentration of Mg 2 ion in the 500.0 mL of solution.

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