Chemistry, 27.02.2020 23:21 abdullahs4639

Given the following unbalanced chemical equation, how many grams of K2O can be produced from 132 grams of potassium and excess oxygen gas?_K(s) + _O2(g) Imported Asset ___K2O(s)

159.0 grams

318.0 grams

13.95 grams

2.962 x 10-1 grams

Answers: 3

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Answers

Answer from: alex7881

The answer to your question is 159.0 grams

Explanation:

data

mass of K₂O = ?

mass of K = 132 g

Process

1.- Balance the chemical reaction

Chemical reaction

K(s) + O₂ ⇒ K₂O

Reactants Elements Products

1 K 2

2 O 1

This reaction is unbalanced

4K(s) + O₂ ⇒ 2K₂O

Reactants Elements Products

4 K 4

2 O 2

Now the reaction is balanced

2.- Calculate the mass of K₂O

Atomic mass of K = 39 x 4 = 156 g

Molar mass of K₂O = 2[(39 x 2) + 16] = 188 g

156 g of K 188 g of K₂O

132 g of K x

x = (132 x 188) / 156

x = 159.0 grams

Answer from: ikramhamideh

159 grams of K2O can be produced

Explanation:

Step 1: Data given

Mass of potassium = 132 grams

Molar mass of potassium = 39.10 g/mol

Step 2: The balanced equation

4K(s) + O2(g) → 2K2O(s)

Step 3: Calculate moles K

Moles K = mass K / molar mass K

Moles K = 132.0 grams / 39.10 g/mol

Moles K = 3.376 moles

Step 4: Calculate moles K2O

For 4moles K we need 1 mol O2 to produce 2 moles K2O

For 3.376 moles K we'll have 3.376/2 = 1.688 moles K2O

Step 5: Calculate mass K2O

Mass K2O = moles K2O * molar mass K2O

Mass K2O = 1.688 moles * 94.2 g/mol

Mass K2O = 159 grams

159 grams of K2O can be produced

Answer from: Quest

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: $p*v = n*r*t$ $1.25*v = 0.900*0.082*298$ $1.25v = 21.9924$ $v = \dfrac{21.9924}{1.25}$ $v = 17.59392\: \to\: \boxed{\boxed{v\approx 17.6\: l}}\end{array}}\qquad\checkmark$ i hope this . =)

Answer from: Quest

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters

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Given the following unbalanced chemical equation, how many grams of K2O can be produced from 132 gra...

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