1.) You have a beaker with 8 grams of (NH4)2CO3 in it. How many atoms are in the beaker?

The answer to your question is 5.019 x 10²² atoms

Explanation:

Data

mass of ammonium carbonate = 8 g

number of atoms = ?

Process

1.- Calculate the molar mass of (NH₄)₂CO₃

(NH₄)₂CO₃ = (14 x 2) + (1 x 8) + (12 x 1) + (16 x 3)

                 = 28 + 8 + 12 + 48

                 = 96 g

2.- Calculate the number of atoms

                    96 g 6.023 x 10²³ atoms

                       8 g   x

                       x = (8 x 6.023 x 10²³) / 96

                       x = 5.019 x 10²² atoms

There are 5.02*10^22 atoms in the beaker

Explanation:

Step 1: Data given

Mass of (NH4)2CO3 = 8.0 grams

Molar mass (NH4)2CO3 = 96.09 g/mol

Number of Avogadro = 6.022 *10^23 / moles

Step 2: Calculate moles (NH4)2CO3

Moles (NH4)2CO3 = mass (NH4)2CO3 / molar mass

Moles (NH4)2CO3 = 8.0 grams / 96.09 g/mol

Moles (NH4)2CO3 = 0.0833 moles

Step 3: Calculate atoms

Atoms = moles * number of Avogadro

Atoms = 0.0833 moles * 6.022 * 10^23 / mol

Atoms = 5.02 *10^22 atoms

There are 5.02*10^22 atoms in the beaker

c. 75.7

i think that is the right