If 13.2 kg of Al 2 O 3 ( s ) , 50.4 kg of NaOH ( l ) , and 50.4 kg of HF ( g ) react completely, how many kilograms of cryolite will be produced? mass of cryolite produced: kg Na 3 AlF 6

Answer : The mass of cryolite produced will be, 54.38 kg

Solution : Given,

Mass of = 13.2 kg  = 13200 g

Mass of = 50.4 kg  = 50400 g

Mass of = 50.4 kg  = 50400 g

Molar mass of = 101.9 g/mole

Molar mass of = 40 g/mole

Molar mass of = 20 g/mole

Molar mass of = 209.9 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

The mole ratio of and is, 1 : 6 : 12

And, the ratio of given moles of and is, 129.54 : 1260 : 2520

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 1 mole of react to give 2 mole of

So, 129.54 moles of react to give moles of

Now we have to calculate the mass of

Thus, the mass of cryolite produced will be, 54.38 kg

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