How many liters of a 6.0M solution Fe(SCN)2 are needed to prepare 2.0L of a 0.75M solution?

We need 0.25 L of the 6.0 M solution

Explanation:

Step 1: Data given

Molarity of the Fe(SCN)2 solution = 6.0 M

Volume of the 0.75 M solution = 2.0 L

Step 2: Calculate volume

C1*V1 = C2*V2

⇒ with C1 = the initial concentration = 6.0 M

⇒ with V1 = the initial volume = TO BE DETERMINED

⇒ with C2 = the new concentration = 0.75 M

⇒ with V2 = the new volume = 2.0 L

6.0M * V1 = 0.75M * 2.0L

V1 = (0.75 M * 2.0L) / 6.0 M

V1 = 0.25 L

We need 0.25 L of the 6.0 M solution

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.