A buffer solution is prepared by mixing 1.00 L of 0.050 M pentafluorobenzoic acid (C6F5COOH) and 1.00 L of 0.060 M sodium pentafluorobenzoate (NaC6F5COO). The Ka of this weak acid is 0.033. Determine the pH of the buffer solution.

pH = 1.401

Explanation:

Using The Henderson-Hasselbalch Equation

pH = pKa + log [base] / [acid]

Ka = 0.033

pKa = -log Ka

pKa = -log 0.033

pKa = 1.48

[base] = concentration of congugate base = 0.060 M

[acid] = concentration of Acid = 0.050 M

pH = pKa + log([base] / [acid])

pH = 1.48 + log (0.050 / 0.060)

pH = 1.48 + log 0.83

pH = 1.48 - 0.079

pH = 1.401

the pH of the buffer solution is 1.401

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.