If the initial concentration of NOBr is 0.0440 M, the concentration of NOBr after 9.0 seconds is . If the initial concentration of is 0.0440 , the concentration of after 9.0 seconds is . 0.0325 M 0.0276 M 0.0403 M 0.0334 M 0.0342 M

This is an incomplete question, here is a complete question.

If the initial concentration of NOBr is 0.0440 M, the concentration of NOBr after 9.0 seconds is ________.

The reaction

It is a second-order reaction with a rate constant of 0.80 M⁻¹s⁻¹ at 11 °C.

Answer : The concentration of after 9.0 seconds is, 0.00734 M

Explanation :

The integrated rate law equation for second order reaction follows:

where,

k = rate constant = 0.80 M⁻¹s⁻¹

t = time taken  = 142 second

[A] = concentration of substance after time 't' = ?

= Initial concentration = 0.0440 M

Putting values in above equation, we get:

Hence, the concentration of after 9.0 seconds is, 0.00734 M

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the answer would be b i believe