A compound has an empirical formula of CHBr2. If it’s molar mass is 345.6 grams, what is it’s molecular formula

The molecular formula is C2H2Br4

Explanation:

Molar Mass of CHBr2 = 12 + 1 + (2x80) = 12 + 1 + 160 = 173

The molecular formula = n x empirical formula

Molar Mass of the compound = 345.6

Empirical formula = CHBr2

n(CHBr2) = 345.6

n x 173 = 345.6

n = 345.6/173 = 2

Therefore the molecular formula is n(CHBr2) = 2(CHBr2) = C2H2Br4

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.