The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, respectively. At what temperature will the diffusion coefficient have a value of 2.7 x 10-14 m2/s

The temperature of the system will be 1622 K

Explanation:

The equation relating the pre-exponential factor and activation energy follows:

where,

D = diffusion coefficient =

= pre-exponential constant =

= activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

Hence, the temperature of the system will be 1622 K

answer: mole of the gas

answer: mole of the gasexplanation: