What is the chemical formula for the limiting reactant in the reaction shown?

This is an incomplete question, the complete question image is attached below.

Answer : The chemical formula for the limiting reactant is,

Explanation :

In the given image reaction we conclude that, there are 5 molecules of and 4 molecules of present on reactant side of the reaction and there are 2 molecules of , 1 molecule of and 4 molecules of present on product side of the reaction.

Thus, the chemical reaction will be:

From this we conclude that, 5 molecules of react with 4 molecules of that means, is a limiting reactant and is an excess reactant.

Thus, the chemical formula for the limiting reactant is,

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6