Answers: 2
![\frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}](/tpl/images/0524/9528/81ffa.png)
in the cell is 
will be equal to zero.![E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}](/tpl/images/0524/9528/cb590.png)
= 0.10 V![\frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}](/tpl/images/0524/9528/5c0ba.png)
= ?![0.10=0-\frac{0.0592}{2}\log \frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}](/tpl/images/0524/9528/25d4c.png)
![\frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}=4.016\times 10^{-4}](/tpl/images/0524/9528/6ddca.png)
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A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.10 V at 25 ºC...
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