Identify the limiting reactant when 7.81 g of HCl reacts with 5.24 g of NaOH to produce NaCl and H2O

NaOH is limiting

Explanation:

                                 Hcl   +    NaOH        Nacl   + H2O  

Given                     7.81g        5.24g

mol weights           1+35.5     23+16+1

                                 36.5            40

No of Moles        7.81/36.5       5.24/40  

                             0.2139              0.131

No of moles = weight/ molecular weight

No of moles of NaOH is  lower so it is limiting as according to equation one mole of Hcl requires mole of NaOH so equal number of moles are required. NaOH is 0.131 which is far lower than 0.2139

represents arrow in forward direction in equation

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.