A 45.8 mg sample of phosphorus reacts with selenium to form 133 mg of the compound. Part A What is the empirical formula of the phosphorus selenide? Express your answer as a chemical formula. nothing

P4Se3

Explanation:

Applying the Law of Conservation of Mass:

(133 mg total) - (45.8 mg P) = 87.2 mg Se

Dividing by the molar mass,

Phosphorus:-(45.8 mg P) / (30.97376 g P/mol) = 1.4786 mmol P

Selenium:-(87.2 mg Se) / (78.96 g Se/mol) = 1.1044 mmol Se

Divide by the smaller number of millimoles:

(1.4786 mmol P) / 1.1044 mmol = 1.339

(1.1044 mmol Se) / 1.1044 mmol = 1.000

multiply by 3, to get a whole number interger. then round to the nearest whole numbers to find the empirical formula.

Therefore the empirical formula is P4Se3

space exploration has led to the development and technological improvement of many everyday items. (if this answer is wrong i will find the right answer) : )