1. Calculate the momentum of a 1,500 kg car traveling at 6 m/s.

2. A military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. If a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be? (Hint: This is a multi-step problem).

1. The momentum of the car has been 9000 kg.m/s.

2. The final velocity of the airplane has been 27.20 m/s.

Momentum can be described as the time required to bring an object to rest. The momentum has been given as the product of mass and velocity.

1. Momentum  (p) can be expressed as:

Where the mass of the car,

The velocity of the car,

Substituting the values for momentum (p):

The momentum of the car has been 9000 kg.m/s.

2. The new velocity has been calculated with the initial momentum as;

The initial momentum of the airplane has been 234,000 kg.m/s.

The addition of fuel results in the final mass as,

According to the law of conservation of momentum, the initial momentum and final momentum are equal.

Substituting the values:

The final velocity of the airplane has been 27.20 m/s.

For more information about momentum, refer to the link:

link

1.

2.

Explanation:

1.Momentum is given as the product of mass by velocity of an object.

Momentum,

m=1,500kh, v=6m/s

2.Momentum,

m=7800kg, v=30m/s

new mass=7800+800=8600

As mass is increased, so does the resultant velocity as mass is directly proportional to velocity.

i think so it’s will be b yes i believe its

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explanation: