The reaction below is carried out at a different temperature at which Kc=0.055. This time, however, the reaction mixture starts with only the product, [NO]=0.0100M, and no reactants. Find the equilibrium concentrations of N2, O2, and NO at equilibrium. N2(g)+O2(g)⇌2NO(g)

Answer : The concentration of at equilibrium is, 0.0045 M, 0.0045 M and 0.001 M respectively.

Explanation :  Given,

Equilibrium constant = 0.055

[NO] = 0.0100 M

The given chemical reaction is:

Initial conc.       0        0           0.0100

At eqm.             x        x         (0.0100-2x)

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:

x = 0.0045 and x = 0.0057

There are two values of 'x'. But we are neglecting the value of x = 0.0057 because the concentration at equilibrium can not be more than initial concentration.

So, x = 0.0045 M

The concentration of at equilibrium = x = 0.0045 M

The concentration of at equilibrium = x = 0.0045 M

The concentration of at equilibrium = (0.0100-2x) = (0.0100-2(0.0045)) = 0.001 M

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.