Carbon monoxide reacts with oxygen to produce carbon dioxide. If 1.0 L of
carbon monoxide reacts with oxygen at STP, How many liters of oxygen are required to react?

2CO(g) + O2(g) --> 2CO2(g)

We need 0.50 L of O2 to react

Explanation:

Step 1: Data given

Volume of carbon monoxide (CO) = 1.0 L (STP)

Step 2: The balanced equation

2CO(g) + O2(g) → 2CO2(g)

Step 3: Calculate moles CO

22.4 L = 1.0 mol

1.0 L = 1.0 / 22.4 L = 0.0446 moles

Step 4: Calculate moles O2

For 2 moles CO we need 1 mol O2 to produce 2 moles CO2

For 0.0446 moles CO we need 0.0446/2 = 0.0223 moles O2

Step 5: Calculate volume O2

1.0 mol = 22.4 L

0.0223 moles = 0.50 L

We need 0.50 L of O2 to react

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explanation:

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