Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO 3 ( s ) . The equation for the reaction is 2 KClO 3 ⟶ 2 KCl + 3 O 2 Calculate how many grams of O 2 ( g ) can be produced from heating 34.4 g KClO 3 ( s ) .

Grams of oxygen produced = 13.47 grams

Explanation:

Firstly, let's balance the equation of the chemical reaction. Heating potassium trioxochlorate  produces potassium chloride and oxygen molecules.

KClO 3 → KCl + O2

Balance the equation

2KClO3 → 2KCl + 3O2

From the chemical equation 2 moles of KClO3 decompose to produce 2 moles of KCl and 3 moles of Oxygen molecule.

atomic mass of K = 39.1g

atomic mass of Cl = 35.5g

atomic mass of O = 16g

The molecular mass of KClO3 =  39.1 + 35.5 + 16 × 3 = 122.6  g/mol

The mass of 2 moles of KClO3 = 2 × 122.6 = 245.2 g

molecular mass of O2 = 32 g

Mass of 3 moles of oxygen molecule = 3 × 32 = 96  grams

Using proportion

245.2g of KClO3 produces 96 g of oxygen

34.4 g will produce ? grams of Oxygen

Grams of oxygen produced = 34.4 × 96/245.2

Grams of oxygen produced = 3302.4 /245.2

Grams of oxygen produced = 13.4681892333

Grams of oxygen produced = 13.47 grams

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