At 25 °C, how many dissociated OH– ions are there in 1243 mL of an aqueous solution whose pH is 2.07?

The number of ions dissociated are

Explanation:

We are given:

pH = 2.07

Calculating the value of pOH by using equation, we get:

To calculate hydroxide ion concentration, we use the equation to calculate pOH of the solution, which is:

We are given:

pOH = 11.93

Putting values in above equation, we get:

To calculate the number of moles for given molarity, we use the equation:

Molarity of solution =

Volume of solution = 1243 mL = 1.243 L  (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

According to mole concept:

1 mole of a compound contains number of particles

So, number of will contain = number of ions

Hence, the number of ions dissociated are