A student receives a solution of 2.750 M NaOH to titrate with 12.00 mL of an unknown solution of HCl. The titration requires 19.50 mL. What is the Molarity of the unknown solution of HCl? M

1.692 M is the molarity of the unknown solution of HCl.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Putting values in above equation, we get:

1.692 M is the molarity of the unknown solution of HCl.

4.46875 M.

Explanation:

Equation of the reaction

NaOH + HCl --> NaCl + H2O

Molar concentration = number of moles/volume

Number of moles = 2.75 × 0.0195

= 0.0536 mol

By stoichiometry, 1 mole of HCl reacted with 1 mole of NaOH.

Therefore,

Number of moles of HCl = 0.0536 mol.

Molar concentration in 12 ml = 0.0536/0.012

= 4.46876 M.

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