Suppose that in a particular reaction 10.5 grams of HCl (36.5 g/mol) react with excess NaOH and 19.3 grams of NaCl (58.5 g/mol) are isolated from the reaction mixture by crystallization. What is the percent yield of NaCl in the experiement?

The answer to your question is 114.7% the percent is higher than expected.

Explanation:

Data

mass of HCl = 10.5 g

molar mass of HCl = 36.5 g

mass of NaOH = 19.3 g

molar mass of NaOH = 58.5

Process

1.- Write the balanced chemical reaction

                    HCl  +   NaOH   ⇒    NaCl  +  H₂O

2.- Calculate the theoretical yield

                    36.5 g of HCl 58.5 g of NaCl

                     10.5 g of HCl  x

                     x = (10.5 x 58.5)/36.5

                     x = 16.83 g

3.- Calculate the percent yield

                     % yield = (19.3/16.83) x 100

                     % yield = 114.7

h let me think

the answer is 0.42 is that is an option. this question provides no info