2FeCl3 + 3Mg → 3MgCl2 + 2Fe
If 4.5 moles of Mg react, how many moles of FeCl3 will be
produced?
A. 3 moles
B. 4.5 mole
C. 2 moles
D. 9 moles

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               2FeCl₃ + 3Mg ⟶ 3MgCl₂ + 2Fe

n/mol:                     4.5

2 mol of FeCl₃ react with 3 mol of Mg

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