How mamy moles of NaCl will be produced from 83.0g pf Na, assuming Cl2 is available in excess

3.61mole of NaCl

Explanation:

Given parameters:

Mass of  Na = 83g

Unknown:

Number of moles of NaCl produced = ?

Solution:

We write the reaction equation first;

       2Na    +   Cl₂    →    2NaCl

Since Cl₂ is in excess in this reaction, the extent will be determined by how much Na is available.

find the number of Na and relate to that of NaCl

 Number of moles of Na  =

          molar mass of Na = 23g/mole

                                            =    

                                            = 3.61mole

          2 mole of Na    reacted  with 2 mole of NaCl

         3.61 mole of Na will react with 3.61mole of NaCl

what are the two models

explanation:

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.