(ii)
(ii)
carbon dio
(C) 3.115 g of a liquid organic compou
and 1.89
C=12; O= 16; gas constan
ogol a liquid organic compound gave, on combustion, 4.50 g of carbon di
04 $o! water. In a molecular determination it was found that 337 ml of the
compound, measured at 27 °C weight and 750 mm/Hg, weighed 0.890 g. Calculate th
empirical and inolecular formulae for the compound. (HET,
R-0.08206 1 atm mol-'K'; latm = 760mmHg)
(5 Marks)

sure im new too!

explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied