A nonvolatile solute is dissolved in benzene so that it has a mole fraction of 0.227. What is the vapor pressure of the solution? (P° of benzene is 26.5 torr)

The vapor pressure of the solution is ; 20.48 Torr

Given data :

mole fraction of nonvolatile solute in Benzene ( Xm ) = 0.227

pressure of benzene ( P° )  = 26.5 torr

Determine the vapor pressure of the solution

applying the formula below

ΔP = P° * Xm ( 1 )

ΔP  = P° - pressure of solution ( P₁ )

Xm = 0.227

back to equation ( 1 )

26.5 - P₁ = 26.5 * 0.227 ( 2 )   resolving equation ( 2 )

∴ Pressure of the solution ( P₁ ) = 26.5 - ( 26.5 * 0.227  )

                                                    = 20.48 torr

Hence we can conclude that the vapor pressure of the solution is 20.48 torr

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Vapor pressure for solution is: 20.48 Torr

Explanation:

Formula to be applied: ΔP = P° . Xm

ΔP = P° - P'

P° → Vapor pressure of pure solvent

P' → Vapor pressure of solution

Xm = Mole fraction.

Let's replace data → 26.5 Torr - P' = 26.5 Torr . 0.227

P' = - (26.5 Torr . 0.227 - 26.5 Torr) →

the answer is:  

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