At 1045K the partial pressures of an equilibrium mixture of H2O (g), H2 (g), and O2 (g) are .040, .0045, and .0030 respectively. Calculate the value of the equilibrium constant Kp at 1045K

2H2O (g) <--> 2H2 (g) + O2 (g)

Kp = 26337.45

Explanation:

The equilibrium constant, Kp describes the ratio of product and reactant concentrations at equilibrium in terms of partial pressures.

For a gas-phase reaction,

aA(g) + bB(g) ⇋ cC(g) + dD(g)

the expression for Kp is:

Kp = (Pc^c * Pd^d) / (Pa^a * Pb^b)

In this reaction;

2H2O (g) ⇋ 2H2 (g)  + O2 (g)

Kp becomes;

Kp = (Pc^c *) / (Pa^a * Pb^b)

Kp = 0.040^2 / (0.0045^2) * (0.0030^1)

Kp = 0.040^2  / (6.075e-8)

Kp = 26337.45

chemical energy is stored in the chemical bonds of atoms and molecules. it can only be seen when it is released in a chemical reaction. when chemical energy is released, the substance from which the energy came is often changed into an entirely different substance.

this chemical reaction releases energy in the form of light and heat. chemical energy is the potential energy stored in the arrangement of atoms within molecules. breaking chemical bonds requires energy, while forming new chemical bonds releases energy.

the atp molecule can store energy in the form of a high energy phosphate bond joining the terminal phosphate group to the rest of the molecule. in this form,energy can be stored at one location, then moved from one part of the cell to another, where it can be released to drive other biochemical reactions.

the answer is a. co2, this would be colder than the : )

explanation: