During the test of an internal combustion engine, 3.00 L of nitrogen gas at 18.5 °C was compressed suddenly (and irrevers- ibly) to 0.500 L by driving in a piston. In the process, the tempera- ture of the gas increased to 28.1°C. Assume ideal behavior, what is the change in entropy of the gas?

Answer : The change in molar entropy of the sample is -14.22 J/K.mol

Explanation :

To calculate the change in molar entropy we use the formula:

where,

= change in molar entropy

n = number of moles = 1 mole

= final temperature =

= initial temperature =

= final volume = 0.500 L

= initial volume = 3.00 L

= heat capacity diatomic gas =

R = gas constant = 8.314 J/mol.K

Now put all the given values in the above formula, we get:

Therefore, the change in molar entropy of the sample is -14.22 J/K.mol

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