What is the pressure that must be exerted on 300 ML of gas which has been collected at STP so that it may be confined to a volume of 190 ML? Temperature is kept constant.

The answer to your question is P₁ = 0.63 atm

Explanation:

Data

P₁ = x

V₁ = 300 ml

P₂ = 1 atm       STP   P = 1 atm

V₂ = 190 ml

Process

1.- Use Boyle's law to solve this problem

    P₁V₁ = P₂V₂

solve for P₁

        P₁ = P₂V₂/V₁

2.- Substitution

        P₁ = (1)(190)/(300)

3.- Simplification

        P₁ = 190/300

4.- Result

        P₁ = 0.63 atm