Consider a reactant with an order of 1. What effect does that reactant have on the rate equation when the concentration is doubled?

The rate of the reaction gets doubled when the concentration of the reactant is doubled.

Explanation:

We are given:

Order of the reaction = 1

Rate law equation for any order follows:

where, n = order of the reaction

= concentration of the reactant A

Rate law equation for the first order reaction becomes:

      .........(1)

When the concentration of the reactant is doubled, the new rate law becomes:

    .....(2)

Taking the ratio of equation 2 and equation 1, we get:

Hence, the rate of the reaction gets doubled when the concentration of the reactant is doubled.

hi,

the answer is d, it has indefinite shape but definite volume.

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