Consider the sodium borohydride reduction of camphor to isoborneol. A reaction was performed in which 1.400 1.400 g of camphor was reduced by an excess of sodium borohydride to make 1.040 1.040 g of isoborneol. Calculate the theoretical yield and percent yield for this reaction.

The percent yield of isoborneol is 73.24 %

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of camphor = 1.400 g

Molar mass of camphor = 152.23 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of camphor and sodium borohydride follows:

By Stoichiometry of the reaction:

1 mole of camphor produces 1 mole of isoborneol

So, of camphor will produce = of isoborneol

Now, calculating the mass of isoborneol from equation 1, we get:

Molar mass of isoborneol = 154.25 g/mol

Moles of isoborneol = moles

Putting values in equation 1, we get:

To calculate the percentage yield of isoborneol, we use the equation:

Experimental yield of isoborneol = 1.040 g

Theoretical yield of isoborneol = 1.42 g

Putting values in above equation, we get:

Hence, the percent yield of isoborneol is 73.24 %

a. a primary source combines several different accounts of an event. b. a primary source generally benefits from having been written after an event.

explanation:

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.