A compound is 53.31 % C , 11.18 % H , and 35.51 % O by mass. What is its empirical formula? Insert subscripts as needed.

The empirical formula is C2H5O

Explanation:

Step 1: Data given

Suppose the mass of the compound = 100.0 grams

The compound contains:

53.31 % C = 53.31 grams C

11.18 % H = 11.18 grams H

35.51 % O = 35.51 grams O

Step 2: Calculate moles

moles = mass / molar mass

Moles C = 53.31 grams / 12.01 g/mol

Moles C = 4.439 moles

Moles H = 11.18 grams / 1.01 g/mol

Moles H = 11.07 moles

Moles O = 35.51 grams / 16.0 g/mol

Moles O = 2.22 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

C: 4.439 / 2.22 = 2

H: 11.07 / 2.22 = 5

O: 2.22/2.22 = 1

C2H5O

The empirical formula is C2H5O

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

a rain shadow is a dry region of land on the side that is protected against the prevailing winds of a mountain range. the prevailing winds are the winds that occur most of the time in a particular place of the earth

prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.