Arrange the following 0.10 MM solutions in order of increasing acidity: (i) NH4NO3NH4NO3, (ii) NaNO3NaNO3, (iii) CH3COONH4CH3COONH4, (iv) NaFNaF, (v) CH3COONa

The order increasing acidity of the solutions is; CH3COONa ≈ NaF < CH3COONH4 < NH4NO3.

An acidic solution is one whose pH lies between 0 to 6. A salt that undergoes hydrolysis to give an acid will have an acidic pH. Let us now consider the solutions to know which of them will give an acid solution.

The order increasing acidity of the solutions is; CH3COONa ≈ NaF < CH3COONH4 < NH4NO3.

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The answer to the question is

In order of increasing acidity, we have

CH3COONa→NaF→NaNO3→CH3COONH4→NH4NO3

Explanation:

(i) NH4NO3 is an acidic salt as it consists of NH₃ and HNO₃. NH₃ is a weak base and  HNO₃ is a strong acid pH = 5.4

(ii) NaNO3  PH7 produces a neutral solution when dissolved in water

(iii) CH3COONH4 Very concentrated solutions are acidic while low concentration 0.5 M are neutral, pH = 7

(iv) NaF basic as it is formed from  weak acid and  strong base. The strength of the basicity depends on the solution pH 7.4

(v) CH3COONa Basic in small concentration pH  8 or 9

Therefore we have in order of increasing acidity, CH3COONa→NaF→NaNO3→CH3COONH4→NH4NO3

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