Three moles of neon expand isothermally from 0.153 m3 to 0.319 m3 while 4.86 × 103 J of heat flows into the gas. Assuming that neon is an ideal gas, find its temperature.

T= 265 degree

Explanation:

Given. n = 3

Vf = 0.319m3.

Vi = 0.153m3.

Q = 4.86*10^3 J

For external process, change in internal energy is zero

W= Q= 4.86*10^3

Also work done for isothermal process is given by

W= nRT in(vf/vi)

T= w/nR in(vf/vi)

T = 4.86*10^3/3*8.314in(0.319/0.153)

T = 265degree

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

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