In the first 22.0 s of this reaction, the concentration of HBr dropped from 0.590 M to 0.465 M . Calculate the average rate of the reaction in this time interval.

This is an incomplete question, here is a complete question.

Consider the following reaction:

In the first 22.0 s of this reaction, the concentration of HBr dropped from 0.590 M to 0.465 M . Calculate the average rate of the reaction in this time interval.

Answer : The average rate of reaction is,

Explanation :

The given chemical reaction follows:

The average rate of the reaction for disappearance of HBr is given as:

where,

= final concentration of HBr = 0.465 M

= initial concentration of HBr = 0.590 M

= change in time = 22.0 s

Putting values in above equation, we get:

Hence, the average rate of reaction is,

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

the correct answer would be b) volume versus temperature, because they are also directly proportional.