Two glasses labeled A and B contain equal amounts of water at different temperatures. Kim put an antacid tablet into each of the two glasses. The table shows the time taken by the tablet to dissolve completely in the two glasses.

Antacid Experiment
Glass --> Time
A --> 40 seconds
B --> 10 seconds

Which of the following statements is correct?

A. The water in Glass A is warmer than the water in Glass B; therefore, the water particles in Glass A are stationary.

B. The water in Glass A is cooler than the water in Glass B; therefore, the water particles in Glass A are stationary.

C. The water in Glass A is warmer than the water in Glass B; therefore, the particles in Glass A move faster.

D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

Option D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

Explanation:

Solubilities of solutes are enhanced when the temperature is increased.

From the experiment conducted,

It is evident that glass B temperature is higher than glass A temperature, because the solute dissolves faster in glass B than in glass A . This implies that glass A is cooler than glass B, hence the particles in A will move slower than that in B.

D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower

Explanation:

In science, temperature is defined as a measure of the average kinetic energy of the molecules of a substance. The more the velocity of the molecules of a substance, the greater their kinetic energy and the greater their temperature.

When molecules of solvent move faster, they collide more frequently with solute particles hence dissolution occurs faster at a higher temperature and molecular slowed compared to another system at lower temperature and lower molecular speed.

The higher temperature of particles in B will see to the faster dissolution of the antacid in B compared to A

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.