A sheet of steel 1.5 mm thick has nitrogen atmospheres on both sides at 1200°C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 6 × 10−11 m2/s, and the diffusion flux is found to be 1.2 × 10−7 kg/m2·s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 4 kg/m3.
How far into the sheet from this high-pressure side will the concentration be 2.0 kg/m3?
Assume a linear concentration profile.

1.2 × 10−7 kg/m2·s

Explanation:

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the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.