Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid at 25 oC. b) Determine the percent dissociation for the solution.

a) The of acetic acid at is

b) The percent dissociation for the solution is

Explanation:

 cM              0             0

So dissociation constant will be:

Give c= 0.10 M and = ?

Also

Putting in the values we get:

b)  

it means there are 3 atoms of oxygen