A particular refrigerant cools by evaporating liquefied CCl 2F 2. How many kg of the liquid must be evaporated to freeze a tray of water to ice (at zero degrees C)? The tray contains 525 grams water. Molar heat of fusion of ice = 6.01 kJ/mol. Molar heat of vaporization of CCl 2F 2 = 17.4 kJ/mole

Answer : The mass of evaporated must be, 1.217 kg

Explanation :

First we have to calculate the moles of water.

Molar mass of water = 18 g/mol

Now we have to calculate the heat released.

Heat released = Moles of water × Molar heat of fusion of ice

Heat released = 29.17 mol × 6.01 kJ/mol

Heat released = 175.3 kJ

Now we have to calculate the moles of

Heat = Moles of × Molar heat of vaporization of

175.3 kJ = Moles of × 17.4 kJ/mol

Moles of = 10.07 mol

Now we have to calculate the mass of

Molar mass of = 120.9 g/mol

Thus, the mass of evaporated must be, 1.217 kg