The Green Chemistry movement strives to replace hazardous oxidizers, such as chlorine, with innocuous oxidizers such as hydrogen peroxide. Exercise 2.26 describes the Bayer process for synthesizing hydrazine, N_2H_4. For hydrazine synthesis by green chemistry, the overall reaction is as follows. 2NH_3 + H_2O_2 rightarrow N_2H_4 + 2H_2O In this modified process, only two synthesis steps are required. The first step is conversion of acetone, CH_3C(O)CH_3, to acetazine, (CH_3)_2C=N-N=C(CH_3)_2, in aqueous solution at 50 degree C. H_2O_2 + 2CH_3C(O)CH_3 + 2NH_3 rightarrow (CH_3)_2C=N-N=C(CH_3)_2 + 4H_2O The second step is the hydrolysis of acetazine into hydrazine and acetone in aqueous solution at 50 degree C. hydrolysis: (CH_3)_2C=N-N=C(CH_3)_2 + 2H_O rightarrow N_2H_4 + 2CH_3C(O)CH_3 The hydrazine is distilled from the aqueous solution as a hydrate, N_2H_4 middot H_2O. Design a process to produce hydrazine hydrate from ammonia and hydrogen peroxide. The hydrogen peroxide is available as a mixture of 70% hydrogen peroxide in 30% water. a. Use the chemical formulas C_3H_6O for acetone and C_6 H_12 N_2 for acetazine. b. You may assume if acetone and ammonia are in excess in the acetazine synthesis, the H_2O_2 is completely consumed. c. You may assume if H_2O is in excess in the acetazine hydrolysis, the acetazine is completely consumed. d. You may assume all substances in this exercise are soluble in water.

Between 2014 and 2016, more than 25,000 children in flint, michigan, drank water that was contaminated with lead from lead pipes. during this time, the city claimed the water was safe to drink. which of these actions could the city have taken to ensure that the drinking water was free from lead?

The volume of helium in a blimp is 6.28 x 10^9 millimeters. the density of helium in the blimp is .1786 kilogram/meter^3. find the mass of the helium in the blimp.

Maleic acid is a carbon-hydrogen-oxygen compound used in dyeing and finishing fabrics and as a preservative of oils and fats.* in a combustion analysis, a 1.054-g sample of maleic acid yields 1.599 g of co_2 and 0.327 g of h2o.* when 0.609 g of maleic acid is dissolved in 25.00 g of glacial acetic acid, the freezing point drops by 0.82 c. maleic acid does not ionize in glacial acetic acid, which has a freezing-point depression constant of k_{\rm f}=3.90~^\circ {\rm c}/m.* in a titration experiment, a 0.4250- g sample of maleic acid is dissolved in water and requires 34.03 ml of 0.2152 m koh for its complete neutralization.* the ph of 0.215 g of maleic acid in 50.00 ml of aqueous solution is found to be 1.80.part adetermine the empirical formula for maleic acid. enter the atoms in order ofc, h, and o.part bdetermine the molecular formula for maleic acid. enter the atoms in order of c,h, and o.express your answer as a chemical formula.part cbased on the titration data, how many ionizable h atoms are in each molecule of maleic acid, c4h4o4? express your answer as an integer.i got the part a and b which is cho and c4h4o4 respectively, can anyone me for part c? the below is what i have so far from other qa'sfinding the empirical formula for maleic acid, needs this info"a combustion analysis a 1.054-g sample of maleic acid yields 1.599g of and 0.327g of ".the rest of your data is used to find molar mass, molecular formula, equivalent mass, # of h+ ions / molecule & katypically this should be: a 1.054-g sample of maleic acid yields 1.599g of co2 and 0.327g of h2osofind mass using molar masses1.599g of co2 @ (12.01 g carbon) / (44.01 g co2) = 0.436 grams of carbon0.327g of h2o @ (2.016 g hydrogen) / (18.01 g/mol h2o) = 0.037 grams of hydrogen1.054-g sample - 0.436 grams of carbon - 0.037 grams of hydrogen = 0.581 grams of oxygennow use molar masses to find moles0.436 grams of carbon @ 12.01 g/mol = 0.0363 mol c0.037 grams of hydrogen @ 1.008 g/mol = 0.0367 mol h0.581 grams of oxygen @ 16.00 g/mol = 0.0363 mol oyour empirical formula ischo and molecular is c4h4o4