The rate constant for a first order reaction with a single reactant is 7.54x10-4 s-1. If the initial reactant concentration is 1.18 M, what will the reactant concentration be after 8.30 minutes?

Answer : The reactant concentration be after 8.30 minutes is, 0.812 M

Explanation :

Expression for rate law for first order kinetics is given by:

where,

k = rate constant  =

t = time passed by the sample  = 8.30 min = 498 s

a = initial amount of the reactant  = 1.18 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

Therefore, the reactant concentration be after 8.30 minutes is, 0.812 M

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