PLEASE HELP!!

Answer the following questions using the data below:

Data :Trial 1 :Trial 2

Mass of empty crucible with lid: 26.679 grams 26.698 grams

Mass of Mg metal, crucible, and lid: 26.934 grams 27.051 grams

Mass of MgO, crucible, and lid: 27.097 grams 27.274 grams

Balanced Chemical Equation for reaction: 2 MG(s) + O2(g) = 2 MGO(s)

Mass of magnesium for each trial:

Trial 1: 0.255g

Trial 2: 0.353g

Actual yield of magnesium oxide for each trial:

Trial 1: 0.418g

Trial 2: 0.576g

Question 1: Calculate the theoretical yield of MgO for each trial:

Question 2: Determine the percent yield of MgO for your experiment for each trial:

Question 3: Determine the average percent yield of MgO for the two trials: