A 0.350g sample of a large biomolecule was dissolved in 15.0g of benzene, and the freezing point depression was determined to be 0.262oC. Calculate the molar mass of the biomolecule.

The molar mass of the biomolecule is 455.73 g/mol

Explanation:

∆T = m × Kf

m (molality) = ∆T/Kf

∆T = 0.262 °C, Kf of benzene = 5.12 °C/m

m = 0.262/5.12 = 0.0512 mol/kg

Molecular mass of the biomolecule = mass of biomolecule ÷ (molality × mass of benzene in kilograms) = 0.350 ÷ (0.0512 × 15/1000) = 0.350 ÷ 0.000768 = 455.73 g/mol

b is the correct

i believe it is a.) released into

explanation: