Asolution is made by dissolving 1.00 moles of sodium chloride (nacl) in 155 grams of water. if the molal boiling point constant for water (kb) is 0.51 °c/m, what would be the boiling point of this solution? show all of the work needed to solve this problem.

Molality = 1.00 mol/ 0.155 Kg = 6.45 
delta T = m x kb x i 
i = Vant'Hoff factor for NaCl = 2 

delta T = 6.45 x 0.51 x 2 = 6.6 
boiling point = 100 + 6.1 = 106.1 °C 

moles glucose = 15.5 g / 180 g/mol=0.0861 
m = 0.0861 mol/ 0.245 Kg =0.351 
delta T = 0.351 x 1.86 =0.65 
freezing point = - 0.65 °C

BTW all credit goes to Dr.A on Yahoo. It's smarter to check other websites before using up your points.

The correct answer would be b) volume versus temperature, because they are also directly proportional.